Engineering Mechanics of Materials |
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Page 23
... applied to the shaft of Figure H1.23 ( b ) while q is increased proportionately such that the total applied torque over this shaft segment remains at 20 k - ft . 10 k - ft 20 k - ft q = const = 40 k - ft / ft BC D B 10 k - ft 10 k - ft ...
... applied to the shaft of Figure H1.23 ( b ) while q is increased proportionately such that the total applied torque over this shaft segment remains at 20 k - ft . 10 k - ft 20 k - ft q = const = 40 k - ft / ft BC D B 10 k - ft 10 k - ft ...
Page 564
... applied at the joints . If loads were applied in the XY plane at points between the joints , the bending resistance IZ would be required . In any analysis involving bending , the yz set of axes is assumed to comprise the principal axes ...
... applied at the joints . If loads were applied in the XY plane at points between the joints , the bending resistance IZ would be required . In any analysis involving bending , the yz set of axes is assumed to comprise the principal axes ...
Page 571
... APPLIED JOINT LOADS , FREE JOINTS should all equal zero , since external forces are not applied to the arch at these joints . All of these output values , while not zero , are very small when compared to the member forces on a ...
... APPLIED JOINT LOADS , FREE JOINTS should all equal zero , since external forces are not applied to the arch at these joints . All of these output values , while not zero , are very small when compared to the member forces on a ...
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
Copyright | |
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acting allowable angle of twist applied Assume axes axis beam bending cantilever centroidal circle column components compressive Compute Consider constant construct coordinate cross section curve deflection deformation depicted in Figure Determine developed diameter direction discussed elastic element energy equal equation equilibrium Example expressed factor failure flexural force free-body diagram function given inertia joint length limit load material maximum shear stress method modulus moment moments neutral axis normal stress Note obtained plane plot positive principal stresses Problem properties quantity ratio reactions Refer to Figure relation represents resist respect rotation segment shaft shown in Figure slope Solution Solve static steel strain strength structural subjected Substitution supported surface tensile tension theory tion torque torsional unit vertical yield zero