Engineering Mechanics of Materials |
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Page 226
... beam is prismatic ) . Consider two longitudinal planes , one of which contains the u principal axes of inertia and the second the v principal axes of inertia for all cross - sectional areas along the beam . Every beam , therefore , has ...
... beam is prismatic ) . Consider two longitudinal planes , one of which contains the u principal axes of inertia and the second the v principal axes of inertia for all cross - sectional areas along the beam . Every beam , therefore , has ...
Page 630
... beam is 20 MPa . Given : beam width = 0.08 m , beam depth = 0.03 m , and spring constant k = 1000 N / m . When the weight W is statically applied to the system , the springs deform 0.02 m . Beam length L = 5 m . E = 200 GPa . Ignore beam ...
... beam is 20 MPa . Given : beam width = 0.08 m , beam depth = 0.03 m , and spring constant k = 1000 N / m . When the weight W is statically applied to the system , the springs deform 0.02 m . Beam length L = 5 m . E = 200 GPa . Ignore beam ...
Page 691
... beam , find the steel and concrete stresses . Use n = 10 . = 14.37 The cross section described in Problem 14.36 is ... BEAMS - ULTIMATE - STRENGTH METHOD 691 Reinforced Concrete Beams-Ultimate Strength Method.
... beam , find the steel and concrete stresses . Use n = 10 . = 14.37 The cross section described in Problem 14.36 is ... BEAMS - ULTIMATE - STRENGTH METHOD 691 Reinforced Concrete Beams-Ultimate Strength Method.
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a shaft shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress at point stress condition stress element T₁ tensile tension Tmax torque torsional V₁ yield strength yield stress zero σ₁