Engineering Mechanics of Materials |
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Page 416
... Column end conditions discussed in Section 8.4 determine column effective lengths L. , and these lengths differ from the geometric length of the column except in the case where both ends of the columns are pinned . Care must be taken to ...
... Column end conditions discussed in Section 8.4 determine column effective lengths L. , and these lengths differ from the geometric length of the column except in the case where both ends of the columns are pinned . Care must be taken to ...
Page 424
... column is 12 ft long and has dressed cross - sectional dimen- sions 9.5 x 11.5 in . = = Solution . The least cross ... column has the W ( wide - flanged ) shape shown in Figure H8.27 and is fabricated of steel with a yield stress of 50 ...
... column is 12 ft long and has dressed cross - sectional dimen- sions 9.5 x 11.5 in . = = Solution . The least cross ... column has the W ( wide - flanged ) shape shown in Figure H8.27 and is fabricated of steel with a yield stress of 50 ...
Page 425
... column is 8.00 ft long and is pinned at both ends . Determine the critical slenderness ratio for this column and find the safe load for it using the column equations of Figure 8.14 ( b ) . Determine the ratio of this safe load to the ...
... column is 8.00 ft long and is pinned at both ends . Determine the critical slenderness ratio for this column and find the safe load for it using the column equations of Figure 8.14 ( b ) . Determine the ratio of this safe load to the ...
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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Common terms and phrases
acting allowable angle of twist applied Assume axes axis beam bending cantilever centroidal circle column components compressive Compute Consider constant construct coordinate cross section curve deflection deformation depicted in Figure Determine developed diameter direction discussed elastic element energy equal equation equilibrium Example expressed factor failure flexural force free-body diagram function given inertia joint length limit load material maximum shear stress method modulus moment moments neutral axis normal stress Note obtained plane plot positive principal stresses Problem properties quantity ratio reactions Refer to Figure relation represents resist respect rotation segment shaft shown in Figure slope Solution Solve static steel strain strength structural subjected Substitution supported surface tensile tension theory tion torque torsional unit vertical yield zero