## Engineering mechanics of materials |

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Page 653

There are a number of situations, however, in which the walls of the

subjected not only to <rr and a, , but also to az . This situation occurs in cylindrical

containers with closed ends subjected to internal and/or external pressures.

There are a number of situations, however, in which the walls of the

**cylinder**aresubjected not only to <rr and a, , but also to az . This situation occurs in cylindrical

containers with closed ends subjected to internal and/or external pressures.

Page 663

(14.20) Example 14.4 A thin-walled

m and r2 = 0.54 m is subjected to internal pressure p, = 2 MPa. Determine (a) the

absolute maximum shearing stress on the inner surface of the

(14.20) Example 14.4 A thin-walled

**cylinder**with closed ends for which r, = 0.50m and r2 = 0.54 m is subjected to internal pressure p, = 2 MPa. Determine (a) the

absolute maximum shearing stress on the inner surface of the

**cylinder**, (b) the ...Page 666

14.5 The internal pressure in the thick -walled

is increased from atmospheric to 2 MPa. Determine the maximum values of a,, ar,

and az. 14.6 A composite thick -walled

14.5 The internal pressure in the thick -walled

**cylinder**described in Problem 14.2is increased from atmospheric to 2 MPa. Determine the maximum values of a,, ar,

and az. 14.6 A composite thick -walled

**cylinder**is made by shrinking a jacket ...### What people are saying - Write a review

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### Contents

Internal Forces in Members | 1 |

Hollow Circular ShaftsAngle of Twist and Shearing Stresses | 157 |

4i5 Power Transmission | 169 |

Copyright | |

7 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero