## Engineering mechanics of materials |

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Page 274

Back substitution of these values for Cx and C2 into the

division by EIu yields the

given beam and loading. Thus 1 / wL , w . wl? \ .„ . . v = Eru(nx3-24x*-ux) (°^L)

The ...

Back substitution of these values for Cx and C2 into the

**equation**for v anddivision by EIu yields the

**equation**of the elastic curve as a function of x for thegiven beam and loading. Thus 1 / wL , w . wl? \ .„ . . v = Eru(nx3-24x*-ux) (°^L)

The ...

Page 322

Equating these two

term \dPt dvt is a second-order differential and without approximation may be

dropped from the

second ...

Equating these two

**equations**leads to u + ^dpi = \ dpi dvi + dpi vt + u fa.28) Theterm \dPt dvt is a second-order differential and without approximation may be

dropped from the

**equation**. This yields the mathematical form of Castiglianossecond ...

Page 458

the moment

elastic curve for the beam) is written in terms of unknown forces and/or moments.

Thus, in addition to the two constants of integration, the slope and deflection ...

the moment

**equation**for the flexural member (i.e., the differential**equation**of theelastic curve for the beam) is written in terms of unknown forces and/or moments.

Thus, in addition to the two constants of integration, the slope and deflection ...

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### Contents

Internal Forces in Members | 1 |

Hollow Circular ShaftsAngle of Twist and Shearing Stresses | 157 |

4i5 Power Transmission | 169 |

Copyright | |

7 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero