Engineering Mechanics of Materials |
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Page 383
... equilibrium are developed and studied in detail with the aid of a column model . Equilibrium of a system is stable , unstable , or neutral , depending upon whether the potential energy of the system is a minimum , maximum , or constant ...
... equilibrium are developed and studied in detail with the aid of a column model . Equilibrium of a system is stable , unstable , or neutral , depending upon whether the potential energy of the system is a minimum , maximum , or constant ...
Page 384
B. B. Muvdi, J. W. McNabb. Stable equilibrium Unstable equilibrium ( a ) Neutral equilibrium U = constant Relative maximum dU 0 Relative minimum dU de 0 do du do = 0 d'U d02 > 0 < 0 d02 = 0 d02 Minimum potential energy stable equilibrium ...
B. B. Muvdi, J. W. McNabb. Stable equilibrium Unstable equilibrium ( a ) Neutral equilibrium U = constant Relative maximum dU 0 Relative minimum dU de 0 do du do = 0 d'U d02 > 0 < 0 d02 = 0 d02 Minimum potential energy stable equilibrium ...
Page 385
... equilibrium . For neutral equilibrium , imagine a small sphere at rest in a horizontal surface . If the small sphere is displaced slightly from this position of equilibrium and released , it will remain in equilibrium in the new ...
... equilibrium . For neutral equilibrium , imagine a small sphere at rest in a horizontal surface . If the small sphere is displaced slightly from this position of equilibrium and released , it will remain in equilibrium in the new ...
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress at point stress condition stress element T₁ tensile tension Tmax torque torsional V₁ yield strength yield stress zero σ₁