## Engineering mechanics of materials |

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Page 415

Ordinate is "failure" stress • l:\periinentjl values Ordinate is "failure" stress divided

by a

FIGURE 8.11 A very large number of empirical column equations have been

devised ...

Ordinate is "failure" stress • l:\periinentjl values Ordinate is "failure" stress divided

by a

**factor**or**safety**Short and intermediate length columns Long columnsFIGURE 8.11 A very large number of empirical column equations have been

devised ...

Page 490

to the allowable stress provides a measure of the margin of safety in a given

design and is given the name "

symbol N. Thus failure-causing stress N = T. rr-f (10.1) allnu/ahlp stress » » For ...

to the allowable stress provides a measure of the margin of safety in a given

design and is given the name "

**factor of safety**" and denoted in this text by thesymbol N. Thus failure-causing stress N = T. rr-f (10.1) allnu/ahlp stress » » For ...

Page 496

Thus the

part AB, where the

now used for what had been known as American Standard steel I sections. .4 ...

Thus the

**factor of safety**in part BC is 250/64.17 = 4, which is larger than that forpart AB, where the

**factor of safety**is 3. * The S designation (see Appendix E) isnow used for what had been known as American Standard steel I sections. .4 ...

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### Contents

Internal Forces in Members | 1 |

Hollow Circular ShaftsAngle of Twist and Shearing Stresses | 157 |

4i5 Power Transmission | 169 |

Copyright | |

7 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero