Engineering Mechanics of Materials |
From inside the book
Results 1-3 of 54
Page 258
... bending case as two separate cases of symmetric bending occurring simultaneously . In other words , the flexural stress at any location in a given cross section will be the algebraic sum of the stresses produced by M , and by M ,. Thus ...
... bending case as two separate cases of symmetric bending occurring simultaneously . In other words , the flexural stress at any location in a given cross section will be the algebraic sum of the stresses produced by M , and by M ,. Thus ...
Page 260
... flexural stress occurs at the position along the beam where the bending moment is a maximum - at the fixed end of the beam . At this position = M = 150 × 103 ft - lb = 1800 × 103 in . - lb This ... stress is 260 CH . 5 / STRESSES IN BEAMS.
... flexural stress occurs at the position along the beam where the bending moment is a maximum - at the fixed end of the beam . At this position = M = 150 × 103 ft - lb = 1800 × 103 in . - lb This ... stress is 260 CH . 5 / STRESSES IN BEAMS.
Page 263
B. B. Muvdi, J. W. McNabb. flexural stress produced at point A by M , is tension . The quantity v represents the ... FLEXURAL STRESSES DUE TO UNSYMMETRIC BENDING OF BEAMS 263.
B. B. Muvdi, J. W. McNabb. flexural stress produced at point A by M , is tension . The quantity v represents the ... FLEXURAL STRESSES DUE TO UNSYMMETRIC BENDING OF BEAMS 263.
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
Copyright | |
14 other sections not shown
Other editions - View all
Common terms and phrases
absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a shaft shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress at point stress condition stress element T₁ tensile tension Tmax torque torsional V₁ yield strength yield stress zero σ₁