## Engineering mechanics of materials |

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Page 258

The determination of the

unsymmetric bending is facilitated, as stated earlier, ... In other words, the

stresses ...

The determination of the

**flexural stress**produced under conditions ofunsymmetric bending is facilitated, as stated earlier, ... In other words, the

**flexural****stress**at any location in a given cross section will be the algebraic sum of thestresses ...

Page 260

The maximum tensile

the bending moment is a maximum — at the fixed end of the beam. At this

position M = 150 x 103 ft-lb = 1800 x 103 in.-lb This moment, and its two

perpendicular ...

The maximum tensile

**flexural stress**occurs at the position along the beam wherethe bending moment is a maximum — at the fixed end of the beam. At this

position M = 150 x 103 ft-lb = 1800 x 103 in.-lb This moment, and its two

perpendicular ...

Page 263

distance from this point to the u axis and is found from the geometry of the section

to be vA = (0.1146) cos 17 + (0.0054) sin 17 = 0.1112 m The second term in ...

**flexural stress**produced at point A by Mu is tension. The quantity v represents thedistance from this point to the u axis and is found from the geometry of the section

to be vA = (0.1146) cos 17 + (0.0054) sin 17 = 0.1112 m The second term in ...

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### Contents

Internal Forces in Members | 1 |

Hollow Circular ShaftsAngle of Twist and Shearing Stresses | 157 |

4i5 Power Transmission | 169 |

Copyright | |

7 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero