## Engineering mechanics of materials |

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Page 3

In order to determine FA , FB, and Fc , apply the equation £ Fx = 0 to each of the

Pi ~ Pi = 0 FB=Pl- P2 Figure 1.1(d): Fc + Pi + Pi ~ Pi = 0 Fe-Pi-Pj-Pa An

alternative ...

In order to determine FA , FB, and Fc , apply the equation £ Fx = 0 to each of the

**free**-**body diagrams**shown. Figure 1.1(b): FA - P, = 0 FA = Px Figure 1.1(c): Fb +Pi ~ Pi = 0 FB=Pl- P2 Figure 1.1(d): Fc + Pi + Pi ~ Pi = 0 Fe-Pi-Pj-Pa An

alternative ...

Page 12

3 is attached to a column at its right end and loaded as shown. Find the reaction

R required to maintain equilibrium of the bar. Draw the

required to determine the axial forces in this bar, then plot the axial force diagram

for it.

3 is attached to a column at its right end and loaded as shown. Find the reaction

R required to maintain equilibrium of the bar. Draw the

**free**-**body diagrams**required to determine the axial forces in this bar, then plot the axial force diagram

for it.

Page 51

Draw axial force, shear, and moment diagrams for this beam. Cut a vertical

section 5 ft to the right of A and compute the axial force, shear, and moment

acting at this section by considering both left and right

Compare these ...

Draw axial force, shear, and moment diagrams for this beam. Cut a vertical

section 5 ft to the right of A and compute the axial force, shear, and moment

acting at this section by considering both left and right

**free**-**body diagrams**.Compare these ...

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### Contents

Internal Forces in Members | 1 |

Hollow Circular ShaftsAngle of Twist and Shearing Stresses | 157 |

4i5 Power Transmission | 169 |

Copyright | |

7 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero