Engineering Mechanics of Materials |
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Page 3
... free - body diagram shown in Figure 1.1 ( e ) : -Fc - P40 Fc - PA = In general , either left or right free - body diagrams may be chosen for determina- tion of the internal forces . The choice is one of convenience . It is readily seen ...
... free - body diagram shown in Figure 1.1 ( e ) : -Fc - P40 Fc - PA = In general , either left or right free - body diagrams may be chosen for determina- tion of the internal forces . The choice is one of convenience . It is readily seen ...
Page 12
... free - body diagrams required to deter- mine the axial forces in this bar , then plot the axial force diagram for it . Column 6k 18 k 12 k B 6 ft 4 ft 6 ft 5 ft- FIGURE H1.5 10 k B C D R 2 k 2 ft 2 ft +21 FIGURE H1.3 2 ft- 1.4 The bar ...
... free - body diagrams required to deter- mine the axial forces in this bar , then plot the axial force diagram for it . Column 6k 18 k 12 k B 6 ft 4 ft 6 ft 5 ft- FIGURE H1.5 10 k B C D R 2 k 2 ft 2 ft +21 FIGURE H1.3 2 ft- 1.4 The bar ...
Page 51
... diagrams . 20 k A 40 k - ft Во 10 ft 10 ft 20 ft FIGURE H1.62 20 k force , shear , and moment diagrams for ABC . Draw a free - body diagram consisting of segment AB by pass- ing a vertical section through the member just to the left of ...
... diagrams . 20 k A 40 k - ft Во 10 ft 10 ft 20 ft FIGURE H1.62 20 k force , shear , and moment diagrams for ABC . Draw a free - body diagram consisting of segment AB by pass- ing a vertical section through the member just to the left of ...
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress at point stress condition stress element T₁ tensile tension Tmax torque torsional V₁ yield strength yield stress zero σ₁