Engineering Mechanics of Materials |
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Page 287
... function into Eq . 6.12 and perform the necessary integrations required to express shear , moment , slope , and deflection of the beam as functions of x . Sketch these functions and check to see that all boundary conditions are met . w ...
... function into Eq . 6.12 and perform the necessary integrations required to express shear , moment , slope , and deflection of the beam as functions of x . Sketch these functions and check to see that all boundary conditions are met . w ...
Page 288
... function into Eq . 6.12 and derive equations for shear , moment , slope , and deflection as functions of x . Sketch these functions and check to see that all boundary condi- tions are satisfied . บ Substitute the given loading intensity ...
... function into Eq . 6.12 and derive equations for shear , moment , slope , and deflection as functions of x . Sketch these functions and check to see that all boundary condi- tions are satisfied . บ Substitute the given loading intensity ...
Page 289
... function w ( x ) into Eq . 6.12 and perform the necessary integrations required to express shear , moment , slope , and deflection as functions of x . Sketch these functions and check to see that boundary conditions at both ends of the ...
... function w ( x ) into Eq . 6.12 and perform the necessary integrations required to express shear , moment , slope , and deflection as functions of x . Sketch these functions and check to see that boundary conditions at both ends of the ...
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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Common terms and phrases
acting allowable angle of twist applied Assume axes axis beam bending cantilever centroidal circle column components compressive Compute Consider constant construct coordinate cross section curve deflection deformation depicted in Figure Determine developed diameter direction discussed elastic element energy equal equation equilibrium Example expressed factor failure flexural force free-body diagram function given inertia joint length limit load material maximum shear stress method modulus moment moments neutral axis normal stress Note obtained plane plot positive principal stresses Problem properties quantity ratio reactions Refer to Figure relation represents resist respect rotation segment shaft shown in Figure slope Solution Solve static steel strain strength structural subjected Substitution supported surface tensile tension theory tion torque torsional unit vertical yield zero