Engineering Mechanics of Materials |
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Page 246
... given the symbol Q. Making these substi- tutions in Eq . 5.11g , we obtain the equation for the horizontal shear stress tx on any surface at a distance v from the neutral axis . Thus vx xv Tux = V .. Q hl , ( 5.12a ) As stated earlier ...
... given the symbol Q. Making these substi- tutions in Eq . 5.11g , we obtain the equation for the horizontal shear stress tx on any surface at a distance v from the neutral axis . Thus vx xv Tux = V .. Q hl , ( 5.12a ) As stated earlier ...
Page 258
... given by Eq . 5.10a . Also , the moment M ,, acting alone , would produce symmetric bending of the section about the principal centroidal axis and , consequently , the flexural stress at the same location in the section would be given ...
... given by Eq . 5.10a . Also , the moment M ,, acting alone , would produce symmetric bending of the section about the principal centroidal axis and , consequently , the flexural stress at the same location in the section would be given ...
Page 373
... given material and is assumed , in this section to be numerically the same in tension and in compression . The ... given by Eq . 7.10b reaches the critical value of the material given by Eq . 7.11 . Thus 1 + μ - − - [ ( 01 − 02 ) 2 + ...
... given material and is assumed , in this section to be numerically the same in tension and in compression . The ... given by Eq . 7.10b reaches the critical value of the material given by Eq . 7.11 . Thus 1 + μ - − - [ ( 01 − 02 ) 2 + ...
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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Common terms and phrases
acting allowable angle of twist applied Assume axes axis beam bending cantilever centroidal circle column components compressive Compute Consider constant construct coordinate cross section curve deflection deformation depicted in Figure Determine developed diameter direction discussed elastic element energy equal equation equilibrium Example expressed factor failure flexural force free-body diagram function given inertia joint length limit load material maximum shear stress method modulus moment moments neutral axis normal stress Note obtained plane plot positive principal stresses Problem properties quantity ratio reactions Refer to Figure relation represents resist respect rotation segment shaft shown in Figure slope Solution Solve static steel strain strength structural subjected Substitution supported surface tensile tension theory tion torque torsional unit vertical yield zero