Engineering Mechanics of Materials |
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Page 147
... length of 0.2 m is subjected to a tensile load of 60,000 N. The 0.03 - m dimension changed to 0.02999 m and the 0.2 m gage length changed to 0.2002 m . If the behavior of the material is assumed to be within the range of propor ...
... length of 0.2 m is subjected to a tensile load of 60,000 N. The 0.03 - m dimension changed to 0.02999 m and the 0.2 m gage length changed to 0.2002 m . If the behavior of the material is assumed to be within the range of propor ...
Page 408
... length equals twice the actual length . Substitution of this effective length into Eq . 8.21 yields a critical load : Pe = 1 π ? ΕΙ 4 L ( 8.23 ) The column with one end free and the other end fixed will buckle elastically at a load that ...
... length equals twice the actual length . Substitution of this effective length into Eq . 8.21 yields a critical load : Pe = 1 π ? ΕΙ 4 L ( 8.23 ) The column with one end free and the other end fixed will buckle elastically at a load that ...
Page 444
... length L. If subjected to a temperature change AT , the bar would experience a change in length equal to a ( AT ) L . If this prismatic bar , however , were restrained so that the change in length could not occur in part or in whole ...
... length L. If subjected to a temperature change AT , the bar would experience a change in length equal to a ( AT ) L . If this prismatic bar , however , were restrained so that the change in length could not occur in part or in whole ...
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a shaft shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress at point stress condition stress element T₁ tensile tension Tmax torque torsional V₁ yield strength yield stress zero σ₁