Engineering Mechanics of Materials |
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Page 141
... elastic range and it is measured by the modulus of elasticity . For example , steels with a modulus of elasticity of about 30 × 106 psi are stiffer than aluminums , with a modulus of elasticity of about 10 x 106 psi . YIELD POINT . The ...
... elastic range and it is measured by the modulus of elasticity . For example , steels with a modulus of elasticity of about 30 × 106 psi are stiffer than aluminums , with a modulus of elasticity of about 10 x 106 psi . YIELD POINT . The ...
Page 147
... modulus of elasticity . ( b ) Poisson's ratio . ( c ) The modulus of resilience . 3.17 A compressive force of 200,000 N is gradually applied to a prismatic bar whose cross section is 0.03 m × 0.04 m and whose length is 0.1 m . The 0.03 ...
... modulus of elasticity . ( b ) Poisson's ratio . ( c ) The modulus of resilience . 3.17 A compressive force of 200,000 N is gradually applied to a prismatic bar whose cross section is 0.03 m × 0.04 m and whose length is 0.1 m . The 0.03 ...
Page 208
... modulus of elasticity . ( c ) Plot the linear portion of the shearing stress- strain curve . ( d ) Determine the modulus of resilience . Torque Angle of Twist ( k - in . ) ( deg ) Torque ( k - in . ) Angle of Twist ( e ) Determine the ...
... modulus of elasticity . ( c ) Plot the linear portion of the shearing stress- strain curve . ( d ) Determine the modulus of resilience . Torque Angle of Twist ( k - in . ) ( deg ) Torque ( k - in . ) Angle of Twist ( e ) Determine the ...
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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acting allowable angle of twist applied Assume axes axis beam bending cantilever centroidal circle column components compressive Compute Consider constant construct coordinate cross section curve deflection deformation depicted in Figure Determine developed diameter direction discussed elastic element energy equal equation equilibrium Example expressed factor failure flexural force free-body diagram function given inertia joint length limit load material maximum shear stress method modulus moment moments neutral axis normal stress Note obtained plane plot positive principal stresses Problem properties quantity ratio reactions Refer to Figure relation represents resist respect rotation segment shaft shown in Figure slope Solution Solve static steel strain strength structural subjected Substitution supported surface tensile tension theory tion torque torsional unit vertical yield zero