Engineering Mechanics of Materials |
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Page 55
... perpendicular to the plane on which it acts and it can be either tensile or compressive . A tensile normal stress is one that tends to pull the material particles away from each other , while a compressive normal stress is one that ...
... perpendicular to the plane on which it acts and it can be either tensile or compressive . A tensile normal stress is one that tends to pull the material particles away from each other , while a compressive normal stress is one that ...
Page 116
... perpendicular to that section and represents the resultant of an infinite number of minute forces perpendicular to the cross section and distributed in some manner throughout the cross - sectional area of the member . If the load P is ...
... perpendicular to that section and represents the resultant of an infinite number of minute forces perpendicular to the cross section and distributed in some manner throughout the cross - sectional area of the member . If the load P is ...
Page 231
... perpendicular to the axis of the beam . Its other two planes , parallel to the axis of the beam , are free of any stresses . Also , since the planes on which σ , act are free of shear stresses , it follows that they , as well as any ...
... perpendicular to the axis of the beam . Its other two planes , parallel to the axis of the beam , are free of any stresses . Also , since the planes on which σ , act are free of shear stresses , it follows that they , as well as any ...
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
Copyright | |
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Common terms and phrases
acting allowable angle of twist applied Assume axes axis beam bending cantilever centroidal circle column components compressive Compute Consider constant construct coordinate cross section curve deflection deformation depicted in Figure Determine developed diameter direction discussed elastic element energy equal equation equilibrium Example expressed factor failure flexural force free-body diagram function given inertia joint length limit load material maximum shear stress method modulus moment moments neutral axis normal stress Note obtained plane plot positive principal stresses Problem properties quantity ratio reactions Refer to Figure relation represents resist respect rotation segment shaft shown in Figure slope Solution Solve static steel strain strength structural subjected Substitution supported surface tensile tension theory tion torque torsional unit vertical yield zero