Engineering Mechanics of Materials |
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Page 55
... perpendicular to the plane on which it acts and it can be either tensile or compressive . A tensile normal stress is one that tends to pull the material particles away from each other , while a compressive normal stress is one that ...
... perpendicular to the plane on which it acts and it can be either tensile or compressive . A tensile normal stress is one that tends to pull the material particles away from each other , while a compressive normal stress is one that ...
Page 116
... perpendicular to that section and represents the resultant of an infinite number of minute forces perpendicular to the cross section and distributed in some manner throughout the cross - sectional area of the member . If the load P is ...
... perpendicular to that section and represents the resultant of an infinite number of minute forces perpendicular to the cross section and distributed in some manner throughout the cross - sectional area of the member . If the load P is ...
Page 231
... perpendicular to the axis of the beam . Its other two planes , parallel to the axis of the beam , are free of any stresses . Also , since the planes on which σ , act are free of shear stresses , it follows that they , as well as any ...
... perpendicular to the axis of the beam . Its other two planes , parallel to the axis of the beam , are free of any stresses . Also , since the planes on which σ , act are free of shear stresses , it follows that they , as well as any ...
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a shaft shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress at point stress condition stress element T₁ tensile tension Tmax torque torsional V₁ yield strength yield stress zero σ₁