## Engineering mechanics of materials |

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Page 218

symmetry, and therefore it is one of the two

The second

obviously, not an axis of symmetry. If it is assumed that b < h, then the moment of

...

symmetry, and therefore it is one of the two

**principal centroidal axes**of inertia.The second

**principal centroidal axis**of inertia is perpendicular to the first and it is,obviously, not an axis of symmetry. If it is assumed that b < h, then the moment of

...

Page 226

Consider, for example, the case of a beam depicted in Figure 5.6(a), whose cross

section, as shown magnified in Figure 5.6(b), has a vertical axis of symmetry.

Obviously, this axis of symmetry is a

as ...

Consider, for example, the case of a beam depicted in Figure 5.6(a), whose cross

section, as shown magnified in Figure 5.6(b), has a vertical axis of symmetry.

Obviously, this axis of symmetry is a

**principal centroidal axis**of inertia (denotedas ...

Page 258

Mv = K/v sin P (5.13e) From the geometry in Figure 5.17 and by using Eqs. 5.13d

and 5.13e, we obtain Equation 5.14 determines the orientation, from the u

terms ...

Mv = K/v sin P (5.13e) From the geometry in Figure 5.17 and by using Eqs. 5.13d

and 5.13e, we obtain Equation 5.14 determines the orientation, from the u

**principal centroidal axis**of inertia, of the neutral axis for unsymmetric bending interms ...

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### Contents

Internal Forces in Members | 1 |

Hollow Circular ShaftsAngle of Twist and Shearing Stresses | 157 |

4i5 Power Transmission | 169 |

Copyright | |

7 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero