Engineering Mechanics of Materials |
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Page 75
... radius , and hence the one provid- ing the absolute maximum shear stress , is the one in the σ1-03 plane for which the radius is ( σ1 - 03 ) / 2 = σ1 / 2 . Thus , once the three principal stresses for a given stress condition are ...
... radius , and hence the one provid- ing the absolute maximum shear stress , is the one in the σ1-03 plane for which the radius is ( σ1 - 03 ) / 2 = σ1 / 2 . Thus , once the three principal stresses for a given stress condition are ...
Page 165
... radius on Rt . This circle intersects the σ , axis at the points with coordinates ( 1 , 0 ) and ( 3,0 ) and by inspection the principal stresses are σ1 = 7 and σ3 = -t . Stress σ1 is tensile and stress σ3 is compressive , and Figure 4.8 ...
... radius on Rt . This circle intersects the σ , axis at the points with coordinates ( 1 , 0 ) and ( 3,0 ) and by inspection the principal stresses are σ1 = 7 and σ3 = -t . Stress σ1 is tensile and stress σ3 is compressive , and Figure 4.8 ...
Page 217
... radius of gyration with respect to the X axis , ry the rectangular radius of gyration with respect to the Y axis , and ro the polar radius of gyration with respect to an axis through point O as shown in Figure 5.2 . xy Note that while ...
... radius of gyration with respect to the X axis , ry the rectangular radius of gyration with respect to the Y axis , and ro the polar radius of gyration with respect to an axis through point O as shown in Figure 5.2 . xy Note that while ...
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
Copyright | |
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acting allowable angle of twist applied Assume axes axis beam bending cantilever centroidal circle column components compressive Compute Consider constant construct coordinate cross section curve deflection deformation depicted in Figure Determine developed diameter direction discussed elastic element energy equal equation equilibrium Example expressed factor failure flexural force free-body diagram function given inertia joint length limit load material maximum shear stress method modulus moment moments neutral axis normal stress Note obtained plane plot positive principal stresses Problem properties quantity ratio reactions Refer to Figure relation represents resist respect rotation segment shaft shown in Figure slope Solution Solve static steel strain strength structural subjected Substitution supported surface tensile tension theory tion torque torsional unit vertical yield zero