Engineering Mechanics of Materials |
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Page 160
... SEGMENT CD ( c ) FIGURE 4.7 1.60 m 60 kN - m x -60 ( m ) 60 kN - m 5 CD Do = 0.24 m D1 = 0.12 m π J = — 32 [ ( 0.24 ) ( 0.12 ) 4 ] = 30.536 × 10-5 m2 Maximum shearing stresses follow from Eq . 4.19 with p each shaft segment : tp = Τρ J ...
... SEGMENT CD ( c ) FIGURE 4.7 1.60 m 60 kN - m x -60 ( m ) 60 kN - m 5 CD Do = 0.24 m D1 = 0.12 m π J = — 32 [ ( 0.24 ) ( 0.12 ) 4 ] = 30.536 × 10-5 m2 Maximum shearing stresses follow from Eq . 4.19 with p each shaft segment : tp = Τρ J ...
Page 169
... segment BC of the shaft depicted in Figure H4.4 and construct Mohr's circle for a surface element . State maximum and minimum normal stresses for this shaft segment and sketch the planes on which these stresses act . 4.17 Refer to ...
... segment BC of the shaft depicted in Figure H4.4 and construct Mohr's circle for a surface element . State maximum and minimum normal stresses for this shaft segment and sketch the planes on which these stresses act . 4.17 Refer to ...
Page 179
... segment where these critical values occur . Determine the angle of twist of each segment of the shaft as viewed by an observer looking from A toward C. 4.35 Refer to Figure H4.33 and determine the maxi- mum shearing stress and normal ...
... segment where these critical values occur . Determine the angle of twist of each segment of the shaft as viewed by an observer looking from A toward C. 4.35 Refer to Figure H4.33 and determine the maxi- mum shearing stress and normal ...
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress at point stress condition stress element T₁ tensile tension Tmax torque torsional V₁ yield strength yield stress zero σ₁