## Engineering mechanics of materials |

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Page 406

8.9 Figure H8.9 shows the cross section of a welded

designed to meet special framing conditions in a building addition. It is axially

loaded and fabricated of welded

32,000 ...

8.9 Figure H8.9 shows the cross section of a welded

**steel**column which wasdesigned to meet special framing conditions in a building addition. It is axially

loaded and fabricated of welded

**steel**and is 16 ft long. If E = 29 x 106 psi, ap =32,000 ...

Page 425

This

slenderness ratio for this column and find the safe load for it using the column

equations of Figure 8.14(b). Determine the ratio of this safe load to the weight of ...

This

**steel**column is 8.00 ft long and is pinned at both ends. Determine the criticalslenderness ratio for this column and find the safe load for it using the column

equations of Figure 8.14(b). Determine the ratio of this safe load to the weight of ...

Page 691

If a moment of 180 k-ft is applied to the beam, find the

. Use n = 10. 14 .37 The cross section described in Problem 14.36 is to be used

for a 10-ft-long cantilever beam. Note that the

...

If a moment of 180 k-ft is applied to the beam, find the

**steel**and concrete stresses. Use n = 10. 14 .37 The cross section described in Problem 14.36 is to be used

for a 10-ft-long cantilever beam. Note that the

**steel**would have to be placed near...

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### Contents

Internal Forces in Members | 1 |

Hollow Circular ShaftsAngle of Twist and Shearing Stresses | 157 |

4i5 Power Transmission | 169 |

Copyright | |

7 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero