Engineering Mechanics of Materials |
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Page 84
... strain between line nn and line tt ( proceeding from nn to tt in a ccw manner ) is nt and represents a decrease in the 90 ° angle . On the other hand , the ... Strain The relations that 84 CH . 2 STRESS , STRAIN , AND THEIR RELATIONSHIPS.
... strain between line nn and line tt ( proceeding from nn to tt in a ccw manner ) is nt and represents a decrease in the 90 ° angle . On the other hand , the ... Strain The relations that 84 CH . 2 STRESS , STRAIN , AND THEIR RELATIONSHIPS.
Page 85
... strain in the direction of the applied stress ( normal longitudinal strain ) , but also a smaller normal strain in a direction perpendicular to the applied stress ( normal transverse strain ) . If the applied normal stress is tensile ...
... strain in the direction of the applied stress ( normal longitudinal strain ) , but also a smaller normal strain in a direction perpendicular to the applied stress ( normal transverse strain ) . If the applied normal stress is tensile ...
Page 92
... strains in a plane are positive . Since the problem under consideration is one of plane strain ( i.e. , one of the three principal strains is zero ) , it follows that the labeling of the three principal strains at the point must be such ...
... strains in a plane are positive . Since the problem under consideration is one of plane strain ( i.e. , one of the three principal strains is zero ) , it follows that the labeling of the three principal strains at the point must be such ...
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a shaft shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress at point stress condition stress element T₁ tensile tension Tmax torque torsional V₁ yield strength yield stress zero σ₁