## Engineering mechanics of materials |

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Page 22

18 is

torsionally fixed at both ends and by symmetry the reacting torques TA and TB

are equal. Determine the internal torque T as a function of x and sketch this

function.

18 is

**subjected**to an external torque that varies sinusoidally as shown. It istorsionally fixed at both ends and by symmetry the reacting torques TA and TB

are equal. Determine the internal torque T as a function of x and sketch this

function.

Page 339

chapter r Combined Stresses and Theories of Failure 7.1 Introduction In the

preceding chapters methods were developed and discussed for the analysis of

members

chapter r Combined Stresses and Theories of Failure 7.1 Introduction In the

preceding chapters methods were developed and discussed for the analysis of

members

**subjected**to one type of load only. For example, Chapter 3 dealt with ...Page 370

Some experimental evidence exists that supports this assumption: Several

materials were

changes in volume but no changes in shape, and no failure by yielding was

detected.

Some experimental evidence exists that supports this assumption: Several

materials were

**subjected**to large hydrostatic pressure, resulting in appreciablechanges in volume but no changes in shape, and no failure by yielding was

detected.

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### Contents

Internal Forces in Members | 1 |

Hollow Circular ShaftsAngle of Twist and Shearing Stresses | 157 |

4i5 Power Transmission | 169 |

Copyright | |

7 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero