## Engineering mechanics of materials |

### From inside the book

Results 1-3 of 92

Page 208

4.54 Data from a

point as shown in Figure 4.25. For the data given below: (a) Find the shearing

modulus of elasticity. (b) Find the equation of the shearing stress-strain line

below ...

4.54 Data from a

**torsional**experiment revealed a well-pronounced**torsional**yieldpoint as shown in Figure 4.25. For the data given below: (a) Find the shearing

modulus of elasticity. (b) Find the equation of the shearing stress-strain line

below ...

Page 339

These are (l) axial and

and flexural loads, and (4)

material is assumed not to be stressed beyond the elastic limit, to justify the use ...

These are (l) axial and

**torsional**loads, (2) axial and flexural loads, (3)**torsional**and flexural loads, and (4)

**torsional**, flexural, and axial loads. In all instances, thematerial is assumed not to be stressed beyond the elastic limit, to justify the use ...

Page 766

... 411-13 slenderness ratio, 397 Combined loads axial and

and axial, 48 flexural axial and

, 345-55 axial and

... 411-13 slenderness ratio, 397 Combined loads axial and

**torsional**, 47 flexuraland axial, 48 flexural axial and

**torsional**, 49 Combined stresses axial and flexural, 345-55 axial and

**torsional**, 339-44**torsional**and flexural, 355-61**torsional**, ...### What people are saying - Write a review

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### Contents

Internal Forces in Members | 1 |

Hollow Circular ShaftsAngle of Twist and Shearing Stresses | 157 |

4i5 Power Transmission | 169 |

Copyright | |

7 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero