## Engineering mechanics of materials |

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Page 601

The fact that the loading in the left span 2P is twice the loading in the right span P

is referred to as proportional loading, ... to Figure 12.14, let Mp = 600 k-in.,/= 1.15,

and L = 30 ft, and determine the following: (a)

The fact that the loading in the left span 2P is twice the loading in the right span P

is referred to as proportional loading, ... to Figure 12.14, let Mp = 600 k-in.,/= 1.15,

and L = 30 ft, and determine the following: (a)

**uniform load**associated with first ...Page 604

-20 n- -10 ft - FIGURE H12.23 12.24 A two-span continuous beam is loaded with

proportional loads as shown in Figure H 12.24. Determine the ... (a) The

...

-20 n- -10 ft - FIGURE H12.23 12.24 A two-span continuous beam is loaded with

proportional loads as shown in Figure H 12.24. Determine the ... (a) The

**uniform****load**associated with the first yield of the simply supported beam. (b) The uniform...

Page 691

If the beam is subjected to a

stresses are 2000 psi and 25,000 psi for concrete and steel, respectively, find w.

This value of w would include the weight of the beam. Deduct this weight per foot

to ...

If the beam is subjected to a

**uniform load**of intensity w and the allowablestresses are 2000 psi and 25,000 psi for concrete and steel, respectively, find w.

This value of w would include the weight of the beam. Deduct this weight per foot

to ...

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### Contents

Internal Forces in Members | 1 |

Hollow Circular ShaftsAngle of Twist and Shearing Stresses | 157 |

4i5 Power Transmission | 169 |

Copyright | |

7 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero