## Engineering mechanics of materials |

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Page 242

(a) Rotate the section so that it offers maximum resistance to the bending action

produced by the

which is to carry a uniform load of intensity 300 lb/ft acting

along ...

(a) Rotate the section so that it offers maximum resistance to the bending action

produced by the

**vertical**load. ... is that for a simply supported beam 20 ft longwhich is to carry a uniform load of intensity 300 lb/ft acting

**vertically**downwardalong ...

Page 253

Determine the

in. below the top of the section. ... Assume the load to act

parallel to the v principal axis of inertia for the cross-sectional area of the ...

Determine the

**vertical**shear stress 5 ft from the right support and (a) In the web, 2in. below the top of the section. ... Assume the load to act

**vertically**downward andparallel to the v principal axis of inertia for the cross-sectional area of the ...

Page 390

Imagine the system in equilibrium in the 0 = 0° or the upright position, and let W

take on a relatively large value associated with point R on the

Figure 8.2(c). Point R corresponds to an unstable equilibrium position. Physically,

W ...

Imagine the system in equilibrium in the 0 = 0° or the upright position, and let W

take on a relatively large value associated with point R on the

**vertical**axis ofFigure 8.2(c). Point R corresponds to an unstable equilibrium position. Physically,

W ...

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### Contents

Internal Forces in Members | 1 |

Hollow Circular ShaftsAngle of Twist and Shearing Stresses | 157 |

4i5 Power Transmission | 169 |

Copyright | |

7 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero