Engineering Mechanics of Materials |
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Page 242
... vertically downward at its free end . ( a ) Rotate the section so that it offers maximum re- sistance to the bending action produced by the vertical load . ( b ) Determine the maximum tensile and compressive stresses induced in the beam ...
... vertically downward at its free end . ( a ) Rotate the section so that it offers maximum re- sistance to the bending action produced by the vertical load . ( b ) Determine the maximum tensile and compressive stresses induced in the beam ...
Page 253
... vertical shear stress 5 ft from the right support and ( a ) In the web , 2 in . below the top of the section . ( b ) At the neutral axis for the section . 5.40 The cross section of the beam is shown in Figure H5.10 . Determine the ...
... vertical shear stress 5 ft from the right support and ( a ) In the web , 2 in . below the top of the section . ( b ) At the neutral axis for the section . 5.40 The cross section of the beam is shown in Figure H5.10 . Determine the ...
Page 390
... vertical axis of Figure 8.2 ( c ) . Point R corresponds to an unstable equilibrium position . Physically , W is so large that the springs are unable to pull the rod back to the vertical position if it is slightly displaced from this ...
... vertical axis of Figure 8.2 ( c ) . Point R corresponds to an unstable equilibrium position . Physically , W is so large that the springs are unable to pull the rod back to the vertical position if it is slightly displaced from this ...
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
Copyright | |
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acting allowable angle of twist applied Assume axes axis beam bending cantilever centroidal circle column components compressive Compute Consider constant construct coordinate cross section curve deflection deformation depicted in Figure Determine developed diameter direction discussed elastic element energy equal equation equilibrium Example expressed factor failure flexural force free-body diagram function given inertia joint length limit load material maximum shear stress method modulus moment moments neutral axis normal stress Note obtained plane plot positive principal stresses Problem properties quantity ratio reactions Refer to Figure relation represents resist respect rotation segment shaft shown in Figure slope Solution Solve static steel strain strength structural subjected Substitution supported surface tensile tension theory tion torque torsional unit vertical yield zero