Engineering Mechanics of Materials |
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Page 141
... YIELD POINT . The yield point , a ,, is the stress at which the material continues to deform without further ... STRENGTH . For materials having a stress - strain diagram such as shown in Figure 3.13 ( those that do not exhibit a well - ...
... YIELD POINT . The yield point , a ,, is the stress at which the material continues to deform without further ... STRENGTH . For materials having a stress - strain diagram such as shown in Figure 3.13 ( those that do not exhibit a well - ...
Page 731
... Yield strength ( 10 psi ) Tensile strength ( 10 psi ) Impact strength , Izod ( ft - lb ) 40 65 85 561 - Creep strength , 00001 % / hr . ( 10 psi ) . 800F 123 900F 1,000F 57 26 Elongation in 2 in . ( % ) 25 Modulus of elasticity ( 10 psi ) ...
... Yield strength ( 10 psi ) Tensile strength ( 10 psi ) Impact strength , Izod ( ft - lb ) 40 65 85 561 - Creep strength , 00001 % / hr . ( 10 psi ) . 800F 123 900F 1,000F 57 26 Elongation in 2 in . ( % ) 25 Modulus of elasticity ( 10 psi ) ...
Page 734
... Yield strength ( 103 psi ) 23 28-44 22-39 21-32 Tensile strength ( 103 psi ) 34 38-53 34-50 33-42 Impact strength , Charpy ( ft - lb ) 20 32 32 Fatigue endurance limit ( 103 psi ) 14 16-23 15-18 16-24 Creep strength , 0 1 % in 100 hr 3 ...
... Yield strength ( 103 psi ) 23 28-44 22-39 21-32 Tensile strength ( 103 psi ) 34 38-53 34-50 33-42 Impact strength , Charpy ( ft - lb ) 20 32 32 Fatigue endurance limit ( 103 psi ) 14 16-23 15-18 16-24 Creep strength , 0 1 % in 100 hr 3 ...
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
Copyright | |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a shaft shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress at point stress condition stress element T₁ tensile tension Tmax torque torsional V₁ yield strength yield stress zero σ₁