## Engineering mechanics of materials |

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Page 141

The proportional limit for a given material represents the value of

which the material no longer behaves in ...

The proportional limit for a given material represents the value of

**stress**beyondwhich the material no longer behaves in ...

**Yield**Point. The**yield**point, ay, is the**stress**at which the material continues to deform without further increase in the ...Page 543

Consider a connection plate | in. thick with a

the combined thickness of the two angles of the connected member exceeds the

plate thickness of ? in., which means that the bearing on the plate is critical.

Consider a connection plate | in. thick with a

**yield stress**of 36 ksi. Assume thatthe combined thickness of the two angles of the connected member exceeds the

plate thickness of ? in., which means that the bearing on the plate is critical.

Page 609

shearing

a solid circular shaft to resist a service maximum torque of 2500 N-m applied at

the center of a 3-m-long shaft which is torsionally fixed at both ends. Use a load ...

shearing

**yield stress**is 300 MPa, select a pipe section for this shaft. 12.40 Designa solid circular shaft to resist a service maximum torque of 2500 N-m applied at

the center of a 3-m-long shaft which is torsionally fixed at both ends. Use a load ...

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### Contents

Internal Forces in Members | 1 |

Hollow Circular ShaftsAngle of Twist and Shearing Stresses | 157 |

4i5 Power Transmission | 169 |

Copyright | |

7 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero