Engineering Mechanics of Materials |
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Page 347
... zero stress for the combined action of F , and M , is sometimes referred to as the neutral axis , but , in this text , to avoid confusion , the term neutral axis is reserved for bending only and the expression fiber or axis of zero ...
... zero stress for the combined action of F , and M , is sometimes referred to as the neutral axis , but , in this text , to avoid confusion , the term neutral axis is reserved for bending only and the expression fiber or axis of zero ...
Page 466
... zero at B to w at C according to the relation wx = ( x / L ) w . The following data are provided : L = 12 ft , E , 10 x 106 psi , I , 70 in.4 , w = EA 2000 lb / ft , = 1 ft , EM = 6 x 106 psi , and the cross- sectional area for the ...
... zero at B to w at C according to the relation wx = ( x / L ) w . The following data are provided : L = 12 ft , E , 10 x 106 psi , I , 70 in.4 , w = EA 2000 lb / ft , = 1 ft , EM = 6 x 106 psi , and the cross- sectional area for the ...
Page 712
... ( zero slope at A ) ( 14.44 ) x = L v = 0 ( zero deflection at B ) ( 14.45 ) x = L v ' v = 0 ( zero slope at B ) ( 14.46 ) The conditions given by Eqs . 14.43 and 14.44 substituted into Eqs . 14.41 and 14.42 reveal that both constants of ...
... ( zero slope at A ) ( 14.44 ) x = L v = 0 ( zero deflection at B ) ( 14.45 ) x = L v ' v = 0 ( zero slope at B ) ( 14.46 ) The conditions given by Eqs . 14.43 and 14.44 substituted into Eqs . 14.41 and 14.42 reveal that both constants of ...
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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acting allowable angle of twist applied Assume axes axis beam bending cantilever centroidal circle column components compressive Compute Consider constant construct coordinate cross section curve deflection deformation depicted in Figure Determine developed diameter direction discussed elastic element energy equal equation equilibrium Example expressed factor failure flexural force free-body diagram function given inertia joint length limit load material maximum shear stress method modulus moment moments neutral axis normal stress Note obtained plane plot positive principal stresses Problem properties quantity ratio reactions Refer to Figure relation represents resist respect rotation segment shaft shown in Figure slope Solution Solve static steel strain strength structural subjected Substitution supported surface tensile tension theory tion torque torsional unit vertical yield zero