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according agricultural allowed already authorities average beginning better Board boys called colleges commune consider course desirable difficulty districts drawing effect elementary England English examination exercise experience fact four France French garden Geography girls give given Greek hand head headmaster higher important inspector instruction interest knowledge language Latin least less lessons masters means methods mind moral natural necessary normal object opinion parents passed perhaps play possible practical preparation Preparatory Schools present primary probably Public Schools pupils question reading reason received regard Report rule rural Sarthe scholarship seems side standard success taken taught teachers teaching things tion town week whole writing young
Page 176 - Prove that parallelograms on the same base and between the same parallels are equal in area.
Page 374 - Rather than that gray king, whose name, a ghost, Streams like a cloud, man-shaped, from mountain peak, And cleaves to cairn and cromlech still...
Page 171 - To describe an isosceles triangle, having each of the angles at the base double of the third angle.
Page 170 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Page 135 - THE sun descending in the west The evening star does shine, The birds are silent in their nest And I must seek for mine, The moon, like a flower In heaven's high bower, With silent delight Sits and smiles on the night...
Page 162 - If the angle of a triangle be divided into two equal angles, by a straight line which also cuts the base ; the segments of the base shall have the same ratio which the other sides of the triangle have to one another...
Page 177 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Page 165 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.