## Engineering mechanics of materials |

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Page 134

B. B. Muvdi, J. W. McNabb. Homework Problems 3.1 Refer to the composite

member shown in Figure H11. 3 and

three parts of the member to be as follows: A AB — 2 in. , ABD = 1 in.2, and ADE

= 3 in.2.

B. B. Muvdi, J. W. McNabb. Homework Problems 3.1 Refer to the composite

member shown in Figure H11. 3 and

**assume**the cross-sectional areas of thethree parts of the member to be as follows: A AB — 2 in. , ABD = 1 in.2, and ADE

= 3 in.2.

Page 136

members to have the same cross-sectional area A = 1 in.2. 3.10 Determine the

tensile stresses and the deformations induced in cables AB and CD in the frame

shown ...

**Assume**the material to have a modulus of elasticity E = 10 x 103 ksi and allmembers to have the same cross-sectional area A = 1 in.2. 3.10 Determine the

tensile stresses and the deformations induced in cables AB and CD in the frame

shown ...

Page 553

the design information contained in Figure 8.14 is applicable if the member is

subjected to compressive loads. Use an allowable stress of 200 MPa if the

member ...

**Assume**that this member is to be fabricated from a structural steel pipe for whichthe design information contained in Figure 8.14 is applicable if the member is

subjected to compressive loads. Use an allowable stress of 200 MPa if the

member ...

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### Contents

Introduction | 1 |

Torsionally Loaded Members in Equilibrium | 14 |

Shear and Bending Moment in Beams | 23 |

Copyright | |

19 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal strains principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero