Engineering Mechanics of Materials |
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Page 134
... assume the cross - sectional areas of the three parts of the member to be as follows : AB = 2 in.2 , ABD = 1 in.2 , and ADE 3 in.2 . Determine : = ( a ) The principal stress of largest magnitude in the composite member . ( b ) The ...
... assume the cross - sectional areas of the three parts of the member to be as follows : AB = 2 in.2 , ABD = 1 in.2 , and ADE 3 in.2 . Determine : = ( a ) The principal stress of largest magnitude in the composite member . ( b ) The ...
Page 136
... Assume the material to have a modulus of elasticity E = 10 × 103 ksi and all members to have the same cross - sectional area A = 1 in.2 . 3.10 Determine the tensile stresses and the deforma- tions induced in cables AB and CD in the ...
... Assume the material to have a modulus of elasticity E = 10 × 103 ksi and all members to have the same cross - sectional area A = 1 in.2 . 3.10 Determine the tensile stresses and the deforma- tions induced in cables AB and CD in the ...
Page 553
... Assume that this member is to be fabricated from a structural steel pipe for which the design infor- mation contained in Figure 8.14 is applicable if the member is subjected to compressive loads . Use an allowable stress of 200 MPa if ...
... Assume that this member is to be fabricated from a structural steel pipe for which the design infor- mation contained in Figure 8.14 is applicable if the member is subjected to compressive loads . Use an allowable stress of 200 MPa if ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length longitudinal M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ vertical yield strength yield stress zero