## Engineering mechanics of materials |

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Page 337

Section 6.9, Problems 6.65 to 6.69. Section 6.10, Problems 6.70 to 6.76. 6S7

Refer to Figure H6.43 and use

at point C of this beam in terms of w, L, E, and /„ . 6.58 Refer to Figure H6.44 and

...

Section 6.9, Problems 6.65 to 6.69. Section 6.10, Problems 6.70 to 6.76. 6S7

Refer to Figure H6.43 and use

**Castigliano's second theorem**to find the deflectionat point C of this beam in terms of w, L, E, and /„ . 6.58 Refer to Figure H6.44 and

...

Page 482

*9.7 Statically Indeterminate Members Under Flexural Loads —

used to satisfy the principle of consistent deformations and therefore to

supplement ...

*9.7 Statically Indeterminate Members Under Flexural Loads —

**Castigliano's****Second Theorem Castigliano's second theorem**as expressed in Eq. 6.29 may beused to satisfy the principle of consistent deformations and therefore to

supplement ...

Page 486

9.69 Solve Problem 9.32 by

9.33 by

9.69 Solve Problem 9.32 by

**Castigliano's second theorem**. 9.70 Solve Problem9.33 by

**Castigliano's second theorem**. 9.71 Solve Problem 9.34 by**Castigliano's****second theorem**. 9.72 Solve Problem 9.35 by**Castigliano's second theorem**.### What people are saying - Write a review

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### Contents

Introduction | 1 |

Torsionally Loaded Members in Equilibrium | 14 |

Shear and Bending Moment in Beams | 23 |

Copyright | |

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal strains principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero