## Engineering mechanics of materials |

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Page 490

B. B. Muvdi, J. W. McNabb. to the

margin of safety in a given design and is given the name " factor of safety " and

denoted in this text by the symbol N. Thus _ failure-causing stress

B. B. Muvdi, J. W. McNabb. to the

**allowable stress**provides a measure of themargin of safety in a given design and is given the name " factor of safety " and

denoted in this text by the symbol N. Thus _ failure-causing stress

**allowable****stress**...Page 504

Refer to Section 13.4 for a discussion of endurance limit. 10.18 Design a solid

shaft of rectangular cross section to resist an applied torque of 25,000 lb-in.

Choose the length of the rectangle to be twice the width. The

Refer to Section 13.4 for a discussion of endurance limit. 10.18 Design a solid

shaft of rectangular cross section to resist an applied torque of 25,000 lb-in.

Choose the length of the rectangle to be twice the width. The

**allowable**shearing**stress**...Page 553

Thus (10.0 - 0.916)(0.800)|^ J(10.0 - 0.916) + (0.916)(7.200)(10.0 - 0.458)j =

2086 psi Thus the maximum horizontal or vertical shear

member is well within the

for the ...

Thus (10.0 - 0.916)(0.800)|^ J(10.0 - 0.916) + (0.916)(7.200)(10.0 - 0.458)j =

2086 psi Thus the maximum horizontal or vertical shear

**stress**occurring in themember is well within the

**allowable**15,000 psi. Therefore, the required sectionfor the ...

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### Contents

Introduction | 1 |

Torsionally Loaded Members in Equilibrium | 14 |

Shear and Bending Moment in Beams | 23 |

Copyright | |

19 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal strains principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero