Engineering Mechanics of Materials |
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Page 435
... aluminum alloy column . ( HINT : In this case σ > 23 ksi . ) 8.46 A solid cylindrical aluminum alloy rod acts as a compression component in a machine . It has a diameter of 0.50 in . and a length of 10.0 in . Column analysis equations ...
... aluminum alloy column . ( HINT : In this case σ > 23 ksi . ) 8.46 A solid cylindrical aluminum alloy rod acts as a compression component in a machine . It has a diameter of 0.50 in . and a length of 10.0 in . Column analysis equations ...
Page 440
... aluminum rod BC and the concrete support DE . The system is subjected to the 500 - kN force . The cross - sectional areas of the aluminum rod and concrete support are are AA A1 = 7 × 10-4 m2 and Ac = 70 × 10-4 m2 , respectively . The ...
... aluminum rod BC and the concrete support DE . The system is subjected to the 500 - kN force . The cross - sectional areas of the aluminum rod and concrete support are are AA A1 = 7 × 10-4 m2 and Ac = 70 × 10-4 m2 , respectively . The ...
Page 452
... aluminum rods at B and C as shown . The length of the aluminum rods is 20 in . and their cross - sectional area A is 1 in.2 . Other needed dimensions are shown in Figure 9.5 ( a ) . Assume the coefficient of thermal expansion for ...
... aluminum rods at B and C as shown . The length of the aluminum rods is 20 in . and their cross - sectional area A is 1 in.2 . Other needed dimensions are shown in Figure 9.5 ( a ) . Assume the coefficient of thermal expansion for ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length longitudinal M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ vertical yield strength yield stress zero