Engineering Mechanics of Materials |
From inside the book
Results 1-3 of 85
Page 241
... beam is subjected to a concentrated force of 50 kN at midspan . ( a ) For a location 3 m from the left support , show the variation of the flexural stress from the inner to the outer fiber . ( b ) Determine the maximum tensile and ...
... beam is subjected to a concentrated force of 50 kN at midspan . ( a ) For a location 3 m from the left support , show the variation of the flexural stress from the inner to the outer fiber . ( b ) Determine the maximum tensile and ...
Page 253
... beam is shown in Figure H5.7 . Determine the vertical shear stress 5 ft from the right support and ( a ) In the web , 2 in . below the top of the section . ( b ) At the neutral axis for the section . 5.40 The cross section of the beam ...
... beam is shown in Figure H5.7 . Determine the vertical shear stress 5 ft from the right support and ( a ) In the web , 2 in . below the top of the section . ( b ) At the neutral axis for the section . 5.40 The cross section of the beam ...
Page 595
... Beams A simply supported beam loaded by a uniform load as shown in Figure 12.14 ( a ) will resist increasing loads until a plastic hinge forms at the center under the action of the fully plastic load , w ,. A larger force cannot be ...
... Beams A simply supported beam loaded by a uniform load as shown in Figure 12.14 ( a ) will resist increasing loads until a plastic hinge forms at the center under the action of the fully plastic load , w ,. A larger force cannot be ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
Copyright | |
14 other sections not shown
Other editions - View all
Common terms and phrases
acting allowable angle of twist applied Assume axes axis beam bending cantilever centroidal circle column components compressive Compute Consider constant construct coordinate cross section curve deflection deformation depicted in Figure Determine developed diameter direction discussed elastic element energy equal equation equilibrium Example expressed factor failure flexural force free-body diagram function given inertia joint length limit load material maximum shear stress method modulus moment moments neutral axis normal stress Note obtained plane plot positive principal stresses Problem properties quantity ratio reactions Refer to Figure relation represents resist respect rotation segment shaft shown in Figure slope Solution Solve static steel strain strength structural subjected Substitution supported surface tensile tension theory tion torque unit yield zero