Engineering Mechanics of Materials |
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Page 177
... coordinate with an origin at A. Compute the maximum shearing stress . and the static angles of twist for both segments of the shaft . 4.27 Refer to Figure H4.25 and construct the torque diagram using a longitudinal coordinate with an ...
... coordinate with an origin at A. Compute the maximum shearing stress . and the static angles of twist for both segments of the shaft . 4.27 Refer to Figure H4.25 and construct the torque diagram using a longitudinal coordinate with an ...
Page 568
... coordinate system , the loading is programmed as a negative intensity with the given magnitude of 0.1 kN / cm . In general , member loads are expressed in terms of local coordinates and joint loads are expressed in terms of global ...
... coordinate system , the loading is programmed as a negative intensity with the given magnitude of 0.1 kN / cm . In general , member loads are expressed in terms of local coordinates and joint loads are expressed in terms of global ...
Page 571
... coordinate system for each member . APPLIED JOINT LOADS , REACTIONS , and FREE JOINT DISPLACEMENTS are given in the global coordinate system . MOMENTS are positive when acting clockwise on a member or a joint , which is consistent with ...
... coordinate system for each member . APPLIED JOINT LOADS , REACTIONS , and FREE JOINT DISPLACEMENTS are given in the global coordinate system . MOMENTS are positive when acting clockwise on a member or a joint , which is consistent with ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length longitudinal M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ vertical yield strength yield stress zero