Engineering Mechanics of Materials |
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Page 659
... cylinder or jacket onto an inner cylinder . Initially , the inside radius of the jacket is a little smaller than the outside radius of the inner cylinder , and the jacket is expanded by heating , for easy placement on the inner cylinder ...
... cylinder or jacket onto an inner cylinder . Initially , the inside radius of the jacket is a little smaller than the outside radius of the inner cylinder , and the jacket is expanded by heating , for easy placement on the inner cylinder ...
Page 660
... cylinder and the inside radius of the jacket because their difference Ar is very small . Assume both jacket and the inner cylinder to be made of the same material . When the shrink - fitting process is completed , the interface pressure ...
... cylinder and the inside radius of the jacket because their difference Ar is very small . Assume both jacket and the inner cylinder to be made of the same material . When the shrink - fitting process is completed , the interface pressure ...
Page 663
... cylinder , and ( c ) the normal and shearing stresses in the wall of the cylinder on a plane inclined to the longitudinal axis of the cylinder through a 30 ° angle . Solution ( a ) Consider a three - dimensional stress element on the ...
... cylinder , and ( c ) the normal and shearing stresses in the wall of the cylinder on a plane inclined to the longitudinal axis of the cylinder through a 30 ° angle . Solution ( a ) Consider a three - dimensional stress element on the ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length longitudinal M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ vertical yield strength yield stress zero