## Engineering mechanics of materials |

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Page 82

Show these stresses on properly oriented elements. oy = 40 MPa FIGURE H2.15

2.7 Concept of Strain at a Point When a nonrigid (deformable) body is subjected

to stresses, it undergoes

Show these stresses on properly oriented elements. oy = 40 MPa FIGURE H2.15

2.7 Concept of Strain at a Point When a nonrigid (deformable) body is subjected

to stresses, it undergoes

**deformations**and distortions. The term**deformation**...Page 87

y dy FIGURE 2.17

strain yxy which rotates line elements such as DB into position D'B'. Note that no

generality ...

y dy FIGURE 2.17

**deformation**in the x direction equal to ex(dxA + dxB), a**deformation**in the y direction equal to ey dy and a distortion due to the shearstrain yxy which rotates line elements such as DB into position D'B'. Note that no

generality ...

Page 126

3.3 Strain and

denned in Section 2.7 as unit

For a prismatic bar such as the one shown in Figure 3.1(a), the strain ex along ...

3.3 Strain and

**Deformation**due to Axial Forces Longitudinal or normal strain wasdenned in Section 2.7 as unit

**deformation**or change in length per unit of length.For a prismatic bar such as the one shown in Figure 3.1(a), the strain ex along ...

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### Contents

Introduction | 1 |

Torsionally Loaded Members in Equilibrium | 14 |

Shear and Bending Moment in Beams | 23 |

Copyright | |

19 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal strains principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero