Engineering Mechanics of Materials |
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Page 344
... diameter aluminum shaft 2 in . diameter steel shaft FIGURE H7.4 7.5 A hollow steel shaft 0.10 m outside diameter is rigidly welded to a 0.06 - m solid steel shaft and sub- jected to the torques and to the compressive axial force as ...
... diameter aluminum shaft 2 in . diameter steel shaft FIGURE H7.4 7.5 A hollow steel shaft 0.10 m outside diameter is rigidly welded to a 0.06 - m solid steel shaft and sub- jected to the torques and to the compressive axial force as ...
Page 503
... diameter is 0.80 of the outside diameter . If the allow- able shearing stress is 12,000 psi and the shaft is to carry a torque of 120,000 lb - in . , determine the cross- sectional dimensions of the shaft . Assume that the angle of ...
... diameter is 0.80 of the outside diameter . If the allow- able shearing stress is 12,000 psi and the shaft is to carry a torque of 120,000 lb - in . , determine the cross- sectional dimensions of the shaft . Assume that the angle of ...
Page 629
... diameter of shaft = 3.0 in . , inside diameter of shaft 2.5 in . , and G = 12.0 x 106 psi . = 13.18 A weight W = 20 lb is dropped from a height h = 4 in onto a simply supported beam as shown in Figure H13.18 . Determine the maximum ...
... diameter of shaft = 3.0 in . , inside diameter of shaft 2.5 in . , and G = 12.0 x 106 psi . = 13.18 A weight W = 20 lb is dropped from a height h = 4 in onto a simply supported beam as shown in Figure H13.18 . Determine the maximum ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length longitudinal M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ vertical yield strength yield stress zero