Engineering Mechanics of Materials |
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Page 141
... ELASTIC LIMIT . The elastic limit , σ , for a given material is the value of stress beyond which the material experiences a permanent deformation even after the stress is removed . Thus , if the material is loaded to any level of stress ...
... ELASTIC LIMIT . The elastic limit , σ , for a given material is the value of stress beyond which the material experiences a permanent deformation even after the stress is removed . Thus , if the material is loaded to any level of stress ...
Page 307
... elastic curve lies above tangent Tangent to elastic curve at point A ( a ) ( b ) Elastic curve Elastic curve Elastic curve Tangent to elastic curve at point B Tangential deviations ( c ) FIGURE 6.14 Tangential deviations Example 6.10 ...
... elastic curve lies above tangent Tangent to elastic curve at point A ( a ) ( b ) Elastic curve Elastic curve Elastic curve Tangent to elastic curve at point B Tangential deviations ( c ) FIGURE 6.14 Tangential deviations Example 6.10 ...
Page 767
... Elastic behavior , 141 Elastic constants related , 103 , 165 Elastic curve , of a beam , 270 , 280 differential equation of , 271 Elastic limit , 141 Elastic range , 140 Elasticity , modulus of , 100 , 141 Elastic strain energy bending ...
... Elastic behavior , 141 Elastic constants related , 103 , 165 Elastic curve , of a beam , 270 , 280 differential equation of , 271 Elastic limit , 141 Elastic range , 140 Elasticity , modulus of , 100 , 141 Elastic strain energy bending ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length longitudinal M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ vertical yield strength yield stress zero