Engineering Mechanics of Materials |
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Page 619
... deformation of the stressed body at the point where the impact takes place U = internal elastic strain energy stored in the stressed body at maximum deformation This quantity U depends upon the nature of the loading . Equations are ...
... deformation of the stressed body at the point where the impact takes place U = internal elastic strain energy stored in the stressed body at maximum deformation This quantity U depends upon the nature of the loading . Equations are ...
Page 629
... elastic strain energy in the shaft . Neglect energy losses during the impact as well as the kinetic energy of the shaft . Determine the maximum shearing stress and the maximum angle of rotation of the shaft for the following input ...
... elastic strain energy in the shaft . Neglect energy losses during the impact as well as the kinetic energy of the shaft . Determine the maximum shearing stress and the maximum angle of rotation of the shaft for the following input ...
Page 767
... Elastic behavior , 141 Elastic constants related , 103 , 165 Elastic curve , of a beam , 270 , 280 differential equation of , 271 Elastic limit , 141 Elastic range , 140 Elasticity , modulus of , 100 , 141 Elastic strain energy bending ...
... Elastic behavior , 141 Elastic constants related , 103 , 165 Elastic curve , of a beam , 270 , 280 differential equation of , 271 Elastic limit , 141 Elastic range , 140 Elasticity , modulus of , 100 , 141 Elastic strain energy bending ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ yield strength yield stress zero σ₁