Engineering Mechanics of Materials |
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Page 82
... element in a body is said to undergo deformation if its length increases or decreases . The term strain of a line element is used to signify its unit deformation ( i.e. , the deformation of the line element divided by its initial length ) ...
... element in a body is said to undergo deformation if its length increases or decreases . The term strain of a line element is used to signify its unit deformation ( i.e. , the deformation of the line element divided by its initial length ) ...
Page 169
... element taken from the shaft surface . State maxi- mum and minimum normal stresses for this element of segment AB and sketch the planes on which these stresses act . 4.15 Determine principal stresses from Mohr's circle constructions for ...
... element taken from the shaft surface . State maxi- mum and minimum normal stresses for this element of segment AB and sketch the planes on which these stresses act . 4.15 Determine principal stresses from Mohr's circle constructions for ...
Page 357
... element at point B is subjected to the shear stress ( Txu ) 1 Tp / J = Fec / J , in which c is the radius of the crank shaft . This same element is not stressed as a result of the action of the bending moment M , in Figure 7.7 ( c ) ...
... element at point B is subjected to the shear stress ( Txu ) 1 Tp / J = Fec / J , in which c is the radius of the crank shaft . This same element is not stressed as a result of the action of the bending moment M , in Figure 7.7 ( c ) ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ yield strength yield stress zero σ₁