Engineering Mechanics of Materials |
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Page 384
... equilibrium energy unstable equilibrium energy neutral equilibrium ( b ) FIGURE 8.1 visual means of recalling the criteria . For stable equilibrium , imagine a small sphere at rest at the lowest point of a concave cylindrical container ...
... equilibrium energy unstable equilibrium energy neutral equilibrium ( b ) FIGURE 8.1 visual means of recalling the criteria . For stable equilibrium , imagine a small sphere at rest at the lowest point of a concave cylindrical container ...
Page 385
... equilibrium . For neutral equilibrium , imagine a small sphere at rest in a horizontal surface . If the small sphere is displaced slightly from this position of equilibrium and released , it will remain in equilibrium in the new ...
... equilibrium . For neutral equilibrium , imagine a small sphere at rest in a horizontal surface . If the small sphere is displaced slightly from this position of equilibrium and released , it will remain in equilibrium in the new ...
Page 390
... equilibrium in the 0 = 0 ° or the upright position , and let W take on a relatively large value associated with point R on the vertical axis of Figure 8.2 ( c ) . Point R corresponds to an unstable equilibrium position . Physically , W ...
... equilibrium in the 0 = 0 ° or the upright position , and let W take on a relatively large value associated with point R on the vertical axis of Figure 8.2 ( c ) . Point R corresponds to an unstable equilibrium position . Physically , W ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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acting allowable angle of twist applied Assume axes axis beam bending cantilever centroidal circle column components compressive Compute Consider constant construct coordinate cross section curve deflection deformation depicted in Figure Determine developed diameter direction discussed elastic element energy equal equation equilibrium Example expressed factor failure flexural force free-body diagram function given inertia joint length limit load material maximum shear stress method modulus moment moments neutral axis normal stress Note obtained plane plot positive principal stresses Problem properties quantity ratio reactions Refer to Figure relation represents resist respect rotation segment shaft shown in Figure slope Solution Solve static steel strain strength structural subjected Substitution supported surface tensile tension theory tion torque unit yield zero