Engineering Mechanics of Materials |
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Page 490
... safety in a given design and is given the name " factor of safety " and denoted in this text by the symbol N. Thus N = failure - causing stress allowable stress ( 10.1 ) For example , if the failure - causing stress is the yield point ...
... safety in a given design and is given the name " factor of safety " and denoted in this text by the symbol N. Thus N = failure - causing stress allowable stress ( 10.1 ) For example , if the failure - causing stress is the yield point ...
Page 504
... factor of safety of N , 3 with respect to fatigue failure . Determine the diameters of these shafts to transmit power as given . Assume that the shaft has minimal stress concentrations which are allowed for in the factor of safety ...
... factor of safety of N , 3 with respect to fatigue failure . Determine the diameters of these shafts to transmit power as given . Assume that the shaft has minimal stress concentrations which are allowed for in the factor of safety ...
Page 636
... factor of safety associated with static ultimate component = factor of safety associated with complete reversal endurance limit ( 0 , 1 ) Sav S , + = 1 Sy / Nu Se / Ne ( 1 , 0 ) Sav Sy / Ny Ny = factor of safety associated with static ...
... factor of safety associated with static ultimate component = factor of safety associated with complete reversal endurance limit ( 0 , 1 ) Sav S , + = 1 Sy / Nu Se / Ne ( 1 , 0 ) Sav Sy / Ny Ny = factor of safety associated with static ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ yield strength yield stress zero σ₁