Engineering Mechanics of Materials |
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Page 490
... safety in a given design and is given the name “ factor of safety " and denoted in this text by the symbol N. Thus N = failure - causing stress allowable stress ( 10.1 ) For example , if the failure - causing stress is the yield point ...
... safety in a given design and is given the name “ factor of safety " and denoted in this text by the symbol N. Thus N = failure - causing stress allowable stress ( 10.1 ) For example , if the failure - causing stress is the yield point ...
Page 504
... factor of safety of N , 3 with respect to fatigue failure . Determine the diameters of these shafts to transmit power as given . Assume that the shaft has minimal stress concentrations which are allowed for in the factor of safety ...
... factor of safety of N , 3 with respect to fatigue failure . Determine the diameters of these shafts to transmit power as given . Assume that the shaft has minimal stress concentrations which are allowed for in the factor of safety ...
Page 636
... factor of safety associated with static ultimate component = factor of safety associated with complete reversal endurance limit = 1 Sav ( 1 , 0 ) Sy / Ny ( 0 , 1 ) Sav Sy / Nu + S , SelNe = 1 ( 1 , 0 ) Sav Sy / Ny Ny = factor of safety ...
... factor of safety associated with static ultimate component = factor of safety associated with complete reversal endurance limit = 1 Sav ( 1 , 0 ) Sy / Ny ( 0 , 1 ) Sav Sy / Nu + S , SelNe = 1 ( 1 , 0 ) Sav Sy / Ny Ny = factor of safety ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
Copyright | |
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acting allowable angle of twist applied Assume axes axis beam bending cantilever centroidal circle column components compressive Compute Consider constant construct coordinate cross section curve deflection deformation depicted in Figure Determine developed diameter direction discussed elastic element energy equal equation equilibrium Example expressed factor failure flexural force free-body diagram function given inertia joint length limit load material maximum shear stress method modulus moment moments neutral axis normal stress Note obtained plane plot positive principal stresses Problem properties quantity ratio reactions Refer to Figure relation represents resist respect rotation segment shaft shown in Figure slope Solution Solve static steel strain strength structural subjected Substitution supported surface tensile tension theory tion torque unit yield zero