## Engineering mechanics of materials |

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Results 1-3 of 70

Page 3

In order to determine FA , FB, and Fc , apply the equation £ Fx = 0 to each of the

- Pi = 0 FB=Pi-P2 Figure 1.1(d): Fc + Pi + Pi - f i = 0 Fc=Pi ~Pi-P3 An alternative ...

In order to determine FA , FB, and Fc , apply the equation £ Fx = 0 to each of the

**free**-**body diagrams**shown. Figure 1.1(b): FA ~ Pi = 0 FA^P, Figure 1.1(c): FB + Pi- Pi = 0 FB=Pi-P2 Figure 1.1(d): Fc + Pi + Pi - f i = 0 Fc=Pi ~Pi-P3 An alternative ...

Page 12

Draw the

then plot the axial force diagram for it. Column FIGURE H1.3 1.4 The bar shown

in Figure H11. 4 is suspended as shown. It is subjected to two applied forces and

...

Draw the

**free**-**body diagrams**required to determine the axial forces in this bar,then plot the axial force diagram for it. Column FIGURE H1.3 1.4 The bar shown

in Figure H11. 4 is suspended as shown. It is subjected to two applied forces and

...

Page 51

Draw axial force, shear, and moment diagrams for this beam. Cut a vertical

section 5 ft to the right of A and compute the axial force, shear, and moment

acting at this section by considering both left and right

Compare these ...

Draw axial force, shear, and moment diagrams for this beam. Cut a vertical

section 5 ft to the right of A and compute the axial force, shear, and moment

acting at this section by considering both left and right

**free**-**body diagrams**.Compare these ...

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### Contents

Introduction | 1 |

Torsionally Loaded Members in Equilibrium | 14 |

Shear and Bending Moment in Beams | 23 |

Copyright | |

19 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal strains principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero