Engineering Mechanics of Materials |
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Page 287
... function into Eq . 6.12 and perform the necessary integrations required to express shear , moment , slope , and deflection of the beam as functions of x . Sketch these functions and check to see that all boundary conditions are met . W ...
... function into Eq . 6.12 and perform the necessary integrations required to express shear , moment , slope , and deflection of the beam as functions of x . Sketch these functions and check to see that all boundary conditions are met . W ...
Page 288
... function into Eq . 6.12 and derive equations for shear , moment , slope , and deflection as functions of x . Sketch these functions and check to see that all boundary condi- tions are satisfied . v Substitute the given loading intensity ...
... function into Eq . 6.12 and derive equations for shear , moment , slope , and deflection as functions of x . Sketch these functions and check to see that all boundary condi- tions are satisfied . v Substitute the given loading intensity ...
Page 289
... function w ( x ) into Eq . 6.12 and perform the necessary integrations required to express shear , moment , slope , and deflection as functions of x . Sketch these functions and check to see that boundary conditions at both ends of the ...
... function w ( x ) into Eq . 6.12 and perform the necessary integrations required to express shear , moment , slope , and deflection as functions of x . Sketch these functions and check to see that boundary conditions at both ends of the ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length longitudinal M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ vertical yield strength yield stress zero