Engineering Mechanics of Materials |
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Page 16
B. B. Muvdi, J. W. McNabb. 20 k - in . -20 in . -30 in . 30 in . Torque ( k - in . ) 20 20 A 30 k - in . 25 k - in . B - < -10 FIGURE 1.8 T1 = T1 - T2 + T3 T1 20-30 +25 = T1 15 k - in . T4 = Та = T1 = 20 k - in . 15 k - in . 15 x ( in . ) ...
B. B. Muvdi, J. W. McNabb. 20 k - in . -20 in . -30 in . 30 in . Torque ( k - in . ) 20 20 A 30 k - in . 25 k - in . B - < -10 FIGURE 1.8 T1 = T1 - T2 + T3 T1 20-30 +25 = T1 15 k - in . T4 = Та = T1 = 20 k - in . 15 k - in . 15 x ( in . ) ...
Page 22
... in.30 in.30 in . D C FIGURE H1.17 X 1.20 A hollow shaft is subjected to the torques shown in Figure H1.20 . Draw the torque diagram for this shaft . 4 k - ft 4 k - ft . 60 k - in . 25 in . E 1.18 The shaft depicted in Figure H1.18 is ...
... in.30 in.30 in . D C FIGURE H1.17 X 1.20 A hollow shaft is subjected to the torques shown in Figure H1.20 . Draw the torque diagram for this shaft . 4 k - ft 4 k - ft . 60 k - in . 25 in . E 1.18 The shaft depicted in Figure H1.18 is ...
Page 344
... in . = 30 k - in . f FIGURE H7.3 15 in . TI = 50 k - in . P = 75 k 7.4 A composite steel shaft is subjected to the torques and to the axial load shown in Figure H7.4 . Determine : ( a ) The principal stresses and the absolute maximum ...
... in . = 30 k - in . f FIGURE H7.3 15 in . TI = 50 k - in . P = 75 k 7.4 A composite steel shaft is subjected to the torques and to the axial load shown in Figure H7.4 . Determine : ( a ) The principal stresses and the absolute maximum ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ yield strength yield stress zero σ₁